Vector V1 is 7.17 units long and points along the -x axis. Vector V2 is 4.05 units long and points at +40.0° t

Vector V1 is 7.17 units long and points along the -x axis. Vector V2 is 4.05 units long and points at +40.0° to the +x axis.

What is the magnitude and direction? I can't find either one. Please explain how to find them, I'm so confused.

find the magnitude of the resultant vector?

take the x and y components for each vector

V1 has x component of -7.17 and y component =0
V2 has x component = 4.05 cos 40 and y component = 4.05 sin 40

add x components; add y components

total x component = -7.17+ 3.10 = -4.07
total y component = 0+ 2.60

magnitude of resultant vector = sqrt[(-4.07)^2 + 2.60^2] = 4.83

direction is given by tan(theta) = y component/x compoent = 2.6/-4.07

direction is in the second quadrant making an angle of 32.6 with the negative x axis