A small fish is dropped by a pelican that is rising steadily at 0.70 m/s.

(Assume the positive direction is upward.)
(a) After 3.5 s, what is the velocity of the fish?
(b) How far below the pelican is the fish after 3.5 s?

Simply you can just use the kinematic equation X=Velocity(initial)times time + 1/2 acceleration (-9.8) times time squared. so D=V initial x time =1/2 acceleration x time^2. For the velocity Final Velocity = initial velocity plus acceleration times time.

Just get a calculator and plug it in. Make sure the signs make sense. And of course you're assuming 9.8 for G and negligible wind resistance.