Hey I got a worksheet for homework and I am not sure if I did this right. Could somebody check my work?
brick is dropped from a bridge. It is seen to hit the water below 3.1 s later. How high is this bridge?
Df = Di + ViT+ 0.5at^2
Df = 0+0+ 0.5 x 9.81 x 3.1^2
Df= 47.14 meters
brick is dropped from a bridge. It is seen to hit the water below 3.1 s later. How high is this bridge?
Df = Di + ViT+ 0.5at^2
Df = 0+0+ 0.5 x 9.81 x 3.1^2
Df= 47.14 meters
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your work is fine, but if you are familiar with significant figures, you should only use two significant figures in your answer, and report a distance of 47m
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Yes, that is correct.
xf = x0 + v0t + (1/2)at^2
xf = 0 + 0t + (1/2)(-9.81)(3.1)^2
xf = -47.1371m
So the bridge is 47.1371m high.
xf = x0 + v0t + (1/2)at^2
xf = 0 + 0t + (1/2)(-9.81)(3.1)^2
xf = -47.1371m
So the bridge is 47.1371m high.