of the hoop. What is the period of its oscillation, assuming that the amplitude is small?
-
I = m*r² + m*r² = 2*.38²*m = .2888*m
For a physical pendulum, T = 2π√[I/mgL] = 2π√[.2888m/(m*9.8*.38)]
T = 1.75 sec
For a physical pendulum, T = 2π√[I/mgL] = 2π√[.2888m/(m*9.8*.38)]
T = 1.75 sec