A circular hoop of radius 38 cm is hung on a narrow horizontal rod and allowed to swing in the plane
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A circular hoop of radius 38 cm is hung on a narrow horizontal rod and allowed to swing in the plane

[From: ] [author: ] [Date: 11-11-17] [Hit: ]
8*.T = 1.......
of the hoop. What is the period of its oscillation, assuming that the amplitude is small?

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I = m*r² + m*r² = 2*.38²*m = .2888*m

For a physical pendulum, T = 2π√[I/mgL] = 2π√[.2888m/(m*9.8*.38)]

T = 1.75 sec
1
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