Explain how much of concentrated acetic acid do you need to prepare 1000 mL of the solution with a pH of 4 (Ka=1.8x10^-5)
Any help would be great.Thanks(:
Any help would be great.Thanks(:
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60.05196 g/mol
add .033362 g to 1000 mL of H2O.
Ka=[H+][A-]/[HA]
[H+]=1 x 10^-4
1.8 x 10^-5=(1 x 10^-4)^2/[HA]
[HA]=5.5 x 10^-4 M
5.5 x 10^-4 mol( 60.05196 g/mol)=.033362g=33.62mg
add .033362 g to 1000 mL of H2O.
Ka=[H+][A-]/[HA]
[H+]=1 x 10^-4
1.8 x 10^-5=(1 x 10^-4)^2/[HA]
[HA]=5.5 x 10^-4 M
5.5 x 10^-4 mol( 60.05196 g/mol)=.033362g=33.62mg