Calcium carbide reacts with water to produce acetylene gas, C2H2, by the following reaction:
CaC2(s) + 2H2O(l) Ca(OH)2(aq) + C2H2(g)
When collected over water, the volume of C2H2 is 4.00L at 0.893atm and 20℃. What mass of CaC2 must have reacted to give this amount of C2H2?
CaC2(s) + 2H2O(l) Ca(OH)2(aq) + C2H2(g)
When collected over water, the volume of C2H2 is 4.00L at 0.893atm and 20℃. What mass of CaC2 must have reacted to give this amount of C2H2?
-
First correct to STP conditions, then calculate mass CaC2.
? L C2H2 = 4.00 L x 0.893 atm / 1 atm x 273 K/ 298 K = 3.27 L
Put in equation weights & volumes from balanced equation.
CaC2(s) + 2H2O(l) Ca(OH)2(aq) + C2H2(g)
64.0 g 22.4 L
? g CaC2 = 3.27 L C2H2 x 64.0 g CaC2 / 22.4 L C2H2 = 9.35 g CaC2
(Since the vapor pressure of water was not given the gas was assumed to be dry)
? L C2H2 = 4.00 L x 0.893 atm / 1 atm x 273 K/ 298 K = 3.27 L
Put in equation weights & volumes from balanced equation.
CaC2(s) + 2H2O(l) Ca(OH)2(aq) + C2H2(g)
64.0 g 22.4 L
? g CaC2 = 3.27 L C2H2 x 64.0 g CaC2 / 22.4 L C2H2 = 9.35 g CaC2
(Since the vapor pressure of water was not given the gas was assumed to be dry)