this was on the test and i took forever on it and could not get it so i missed a bunch of the questions at the end of the test
ive tried everyting and cant seem to get it
f(x) = 3 -Sqrt(1-1x/2)
in words f of x is 3 minus the square root of 1 minus 1/2 x
if anybody can help thanks 10 points!
ive tried everyting and cant seem to get it
f(x) = 3 -Sqrt(1-1x/2)
in words f of x is 3 minus the square root of 1 minus 1/2 x
if anybody can help thanks 10 points!
-
Let x = f(y) and then express y in terms of x:
x = 3 - sqrt(1 - 1y/2)
Subtract 3 from both sides:
x - 3 = -sqrt(1 - 1y/2)
Multiply both sides by negative one:
3 - x = sqrt(1 - 1y/2)
Square both sides:
(3 - x)² = 1 - 1y/2
Expand the left side using the F.O.I.L. method:
First terms
3•3 = 9
Outside terms:
3•-x = -3x
Inside terms:
-x•3 = -3x
Last terms:
-x•-x = x²
Collect the terms:
9 - 3x -3x + x² = 1 - 1y/2
Combine like terms:
9 - 6x + x² = 1 - 1y/2
Subtract 1 from both sides and flip the equation:
-1y/2 = 8 - 6x + x²
Multiply both sides of the equation by -2:
y = -16 + 12x - 2x² ANS
To check this is the inverse function (f^-1(x)) we should verify the property that the inverse function evaluated at the function yields x and viceversa:
f^-1(f(x)) = x
y = -16 + 12x - 2x²
Let x = f(x) = 3 - sqrt(1-1x/2)
y = -16 + 12{3 - sqrt(1-1x/2)} - 2{3 - sqrt(1-1x/2)}²
y = -16 + 36 - 12sqrt(1-1x/2) - 2{9 - 6sqrt(1-1x/2) + 1 - 1x/2}
y = 20 - 12sqrt(1-1x/2) - 18 + 12sqrt(1-1x/2) - 2 + x
y = x
This checks. You should also check that f(f^-1(x)) = x but I will leave that to you.
x = 3 - sqrt(1 - 1y/2)
Subtract 3 from both sides:
x - 3 = -sqrt(1 - 1y/2)
Multiply both sides by negative one:
3 - x = sqrt(1 - 1y/2)
Square both sides:
(3 - x)² = 1 - 1y/2
Expand the left side using the F.O.I.L. method:
First terms
3•3 = 9
Outside terms:
3•-x = -3x
Inside terms:
-x•3 = -3x
Last terms:
-x•-x = x²
Collect the terms:
9 - 3x -3x + x² = 1 - 1y/2
Combine like terms:
9 - 6x + x² = 1 - 1y/2
Subtract 1 from both sides and flip the equation:
-1y/2 = 8 - 6x + x²
Multiply both sides of the equation by -2:
y = -16 + 12x - 2x² ANS
To check this is the inverse function (f^-1(x)) we should verify the property that the inverse function evaluated at the function yields x and viceversa:
f^-1(f(x)) = x
y = -16 + 12x - 2x²
Let x = f(x) = 3 - sqrt(1-1x/2)
y = -16 + 12{3 - sqrt(1-1x/2)} - 2{3 - sqrt(1-1x/2)}²
y = -16 + 36 - 12sqrt(1-1x/2) - 2{9 - 6sqrt(1-1x/2) + 1 - 1x/2}
y = 20 - 12sqrt(1-1x/2) - 18 + 12sqrt(1-1x/2) - 2 + x
y = x
This checks. You should also check that f(f^-1(x)) = x but I will leave that to you.
-
f(x) = 3 - sqrt(1 - x/2)
In order to find the inverse, first switch x and f(x):
x = 3 - sqrt(1 - f(x)/2)
Now, solve for f(x). First, we subtract 3 from each side:
x - 3 = -sqrt(1 - f(x)/2)
Next, multiply through by -1:
3 - x = sqrt(1 - f(x)/2)
Square both sides:
(3 - x)^2 = 1 - f(x)/2
Now, you don't NEED to, but I will expand the left term here for the sake of completeness:
9 - 6x + x^2 = 1 - f(x)/2
Rearrange to a more acceptable form:
x^2 - 6x + 9 = 1 - f(x)/2
Subtract 1 from each side:
x^2 - 6x + 8 = -f(x)/2
Multiply by -2:
-2x^2 + 12x - 16 = f(x)
So, the inverse function is:
f(x) = -2x^2 + 12x - 16
In order to find the inverse, first switch x and f(x):
x = 3 - sqrt(1 - f(x)/2)
Now, solve for f(x). First, we subtract 3 from each side:
x - 3 = -sqrt(1 - f(x)/2)
Next, multiply through by -1:
3 - x = sqrt(1 - f(x)/2)
Square both sides:
(3 - x)^2 = 1 - f(x)/2
Now, you don't NEED to, but I will expand the left term here for the sake of completeness:
9 - 6x + x^2 = 1 - f(x)/2
Rearrange to a more acceptable form:
x^2 - 6x + 9 = 1 - f(x)/2
Subtract 1 from each side:
x^2 - 6x + 8 = -f(x)/2
Multiply by -2:
-2x^2 + 12x - 16 = f(x)
So, the inverse function is:
f(x) = -2x^2 + 12x - 16