connected in parallel with each other. A current of 0.5 A runs through the battery. What is the p.d. between the two resistors in parallel with each other?
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it is 12 - I (10)
= 12 - 0.5(10)
= 7 V <<<<<<<<<
= 12 - 0.5(10)
= 7 V <<<<<<<<<
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It can be presumed that the third resistor (though you didn't say so) is in series with the parallel pair of the other two.
Then, the parallel pair has a resistance of 5 Ohms, in series with the third 10 Ohm resistor. 12 V will drop in proportion (2:1) to 8 V across 10 Ohm resistor & 4 V across the parallel pair, 5 Ohms.
With the total resistance of 15 Ohms across 12 V battery the current would be
12/15 = 0.8 A
& not the 0.5 A, you stated.
All this, 'If' the first sentence (above) holds true.
Then, the parallel pair has a resistance of 5 Ohms, in series with the third 10 Ohm resistor. 12 V will drop in proportion (2:1) to 8 V across 10 Ohm resistor & 4 V across the parallel pair, 5 Ohms.
With the total resistance of 15 Ohms across 12 V battery the current would be
12/15 = 0.8 A
& not the 0.5 A, you stated.
All this, 'If' the first sentence (above) holds true.