Atomic theory questions help
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Atomic theory questions help

[From: ] [author: ] [Date: 11-11-20] [Hit: ]
Also if you can, this is optional but can you also give another sample problem like this after you show the work so I can understand or any good websites that has similar problems to this? Your help will be greatly appreciated. Once again 10 points to whomever gives the most through answer.-Since 1 cm^3 = 1 mL,(BTW,......
The density of beryllium is 1840 kg/cm^3. Convert it to mg/mL. Please express your answer as scientific notation and following the rule of significant figures. I have a test on Monday in science and i am stuck with this question on the review sheet. Can someone tell me how to solve this and also show the steps in to solve it? Also if you can, this is optional but can you also give another sample problem like this after you show the work so I can understand or any good websites that has similar problems to this? Your help will be greatly appreciated. Once again 10 points to whomever gives the most through answer.

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Since 1 cm^3 = 1 mL, we can write this:

1840 kg/mL

(BTW, look at that density. One thousand eight hundred forty kilograms per mL. That's pretty dense.)

Now, we need to convert kg to mg using the following conversion factor:

1 kg = 10^6 mg

1840 kg/mL times 10^6 mg / kg = 1840 x 10^6 mg/mL = 1.840 x 10^9 mg/mL

Some metric conversions and a few videos here:

http://www.chemteam.info/Metric/Metric.h…
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