I need your help with this inverse Laplace Transform:
F(S)=(2-3)/[S(S-3)(S-1)(S+1)]
-->Solve with partial fractions
F(S)=(2-3)/[S(S-3)(S-1)(S+1)]
-->Solve with partial fractions
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forget how to do partial fractions ??
F(s) = a / s + b / [s-3] + c / [ s - 1 ] + d / [ s+1]
multiply both sides by each denominator and then set s = to the value
which makes that denominator have 0 value
ie by [ s- 3] and then set s = 3 to find b { = ( 2-3) / [ 3 * 2 * 4 ] }
did you really mean " 2 - 3 " ??
F(s) = a / s + b / [s-3] + c / [ s - 1 ] + d / [ s+1]
multiply both sides by each denominator and then set s = to the value
which makes that denominator have 0 value
ie by [ s- 3] and then set s = 3 to find b { = ( 2-3) / [ 3 * 2 * 4 ] }
did you really mean " 2 - 3 " ??