What's the derivative of this equation
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What's the derivative of this equation

[From: ] [author: ] [Date: 11-11-11] [Hit: ]
t. x, by Chain Rule,.........
xcos(y)+ysin(x) = 1

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... x cos y + y sin x = 1

∴ diff... w.r.t. x, by Chain Rule,

... d/dx( x cos y ) + d/dx( y sin x ) = d/dx( 1 )

∴ [ x ( -sin y )·y' + ( cos y )·( 1 ) ] + [ y ( cos x ) + ( sin x ). y' ] = 0

∴ ( sin x - x sin y )· y' = - ( cos y + y cos x )

∴ y' = - ( cos y + y cos x ) / ( sin x - x sin y ) ................ Ans.
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You are Welcome, Chris !

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