If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation.
5x - 2y - z = 16
x + y + 4z = 6
3x + 2y + 6z = 16 (1 points)
A) -3y + 19z = -14
5y + 18z = -2
B) 7x + 7z = 28<-----
x - 2z = 4
C) -7y - 21z = -14
-y - 6z = -2
D) 21x - 7y = 70
33x - 10y = 112
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.
3x - 5y + 2z = 7
4x + 9y - z = 2
x - 3y + 3z = 7 (1 points)
A) 11x + 13y = 11<------
13x + 24y = 13
B) 11x + 13y = 11
3x - 5y = 7
C) x - 3y = 7
13x + 24y = 13
D) x - 3y = 7
3x - 5y = 7
Solve the following system of equations.
4x - 2y - z = -5
x - 3y + 2z = 3
3x + y - 2z = -5 (1 points)
A) (0, 1, 3)
B) (0, -1, 3)
C) (0, 1, -3) <----
D) (0, -1, -3)
Im just want to check to see if im right? ugh!
5x - 2y - z = 16
x + y + 4z = 6
3x + 2y + 6z = 16 (1 points)
A) -3y + 19z = -14
5y + 18z = -2
B) 7x + 7z = 28<-----
x - 2z = 4
C) -7y - 21z = -14
-y - 6z = -2
D) 21x - 7y = 70
33x - 10y = 112
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.
3x - 5y + 2z = 7
4x + 9y - z = 2
x - 3y + 3z = 7 (1 points)
A) 11x + 13y = 11<------
13x + 24y = 13
B) 11x + 13y = 11
3x - 5y = 7
C) x - 3y = 7
13x + 24y = 13
D) x - 3y = 7
3x - 5y = 7
Solve the following system of equations.
4x - 2y - z = -5
x - 3y + 2z = 3
3x + y - 2z = -5 (1 points)
A) (0, 1, 3)
B) (0, -1, 3)
C) (0, 1, -3) <----
D) (0, -1, -3)
Im just want to check to see if im right? ugh!
-
- 5x + 2y + z + 5(x + y + 4z) = - 16 + 5(6)
- 5x + 2y + z + 5x + 5y + 20z = - 16 + 30
7y + 21z = 14
y + 3z = 2
Answer: 7y + 21z = 14 OR option C. - 7y - 21z = - 14
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3x - 5y + 2z + 2(4x + 9y - z) = 7 + 2(2)
3x - 5y + 2z + 8x + 18y - 2z = 7 + 4
11x + 13y = 11
Answer: option A. 11x + 13y = 11
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3 equations combined—z:
- 4x + 2y + z + x - 3y + 2z + 3x + y - 2z = 5 + 3 - 5
z = 3
1st equation—y in terms of x, substitute z:
4x - 2y - 3 = - 5
2y = 4x + 2
y = 2x + 1
2nd equation—x, substitute y & z:
x - 3(2x + 1) + 2(3) = 3
x - 6x - 3 + 6 = 3
5x = 0
x = 0
1st equation—y, substitute x:
= 2(0) + 1
= 0 + 1
= 1
Answer: option A) (0, 1, 3)
- 5x + 2y + z + 5x + 5y + 20z = - 16 + 30
7y + 21z = 14
y + 3z = 2
Answer: 7y + 21z = 14 OR option C. - 7y - 21z = - 14
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3x - 5y + 2z + 2(4x + 9y - z) = 7 + 2(2)
3x - 5y + 2z + 8x + 18y - 2z = 7 + 4
11x + 13y = 11
Answer: option A. 11x + 13y = 11
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3 equations combined—z:
- 4x + 2y + z + x - 3y + 2z + 3x + y - 2z = 5 + 3 - 5
z = 3
1st equation—y in terms of x, substitute z:
4x - 2y - 3 = - 5
2y = 4x + 2
y = 2x + 1
2nd equation—x, substitute y & z:
x - 3(2x + 1) + 2(3) = 3
x - 6x - 3 + 6 = 3
5x = 0
x = 0
1st equation—y, substitute x:
= 2(0) + 1
= 0 + 1
= 1
Answer: option A) (0, 1, 3)