Word problem help please!!!!!!!!!!!!

A cyclist travels 154km in 7 hours going against the wind and 156km in 6 hours with the wind. What is the rate of the cyclist in still air and what is the rate of the wind?

TYPE..............RATE...............TIM…
Against............B - W..................7....................…
With.................B + W.................6.....................…

T*R = D

7(B - W) = 154................divide both sides by 7
6(B + W) = 156...............divide both sides by 6

B - W = 22
B + W = 26
**************ADD
2B = 48

B = 24 km/h......ANSWER...Rate of Bike

B + W = 26
24 + W = 26

W = 2 km/h......ANSWER...Rate of Wind

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His speed against the wind is s - w (his speed is reduced by the wind he's riding against); his speed with the wind is s + w ((his speed is increased by the wind at his back).

Since distance equals rate times time:

Into the wind:

D1 = (s - w) * T1

with the wind:

D2 = (s + w) * T2

Fill in the numbers that you know:

154 = (s - w) * 7
156 = (s + w) * 6

Rewrite both equations to put rate on the left side:

s - w = 154 / 7 = 22
s + w = 156 / 6 = 26

Add the two equations to eliminate the w term:

s - w = 22
+(s + w = 26)
----------------
2s = 48

Divide both sides by 2:

s = 24

The cyclist's speed is 24 km/hr.


Since s - w is 22, w = 22.