Solve -4k-2=10 Algebra Help

1. Solve -4k-2=10

2. t/5+3=3

Please help me!

1) K = -3
Work: -4k - 2 = 10 + 2
10 + 2 = 12 -4k = 12
12/-4 = -4k/-4
12/-4=-3
K=-3

2) T=0
Work : T/5 + 3 = 3 - 3
3 - 3 = 0 T/5=0
0/5 = T/5 / 5
0/5 = 0
T=0

You can plug in the variable answers and see that my answers are correct. If you ever need help with Algebra just ask me. ;)

Ok so here are the answers and the explanations, please read the explanations because you need to understand!

1) -4k-2=10
(so you take the -2 from one side and add it to the other side) -4k=10+2
(so you do the sum) -4k=12
(so then you take the -4 from one side and times it onto the other side) k=12/-4
(do the sum) k=-3

2) t/5+3=3
(so you take the +3 from one side and subract it from the other) t/5=3-3
(so the sum is) t/5=0
( then you do the divided by 5 onto the other side making times by 5) t=5x0
(so the answwerr is:) t=0


Hope this helped and PLease please please read the notes and ask your teacher about how to do them if you still dont understand :)

1 get k alone on one side of the equation.
add 2 to both sides ---> -4k=12
divide both sides by -4 ---> k=-12/4
reduce ---> k = -3
check you work by replacing k with -3 and seeing if it is true.

2 get t alone on one side of the equation
subtract 3 from both sides - --> t/5 = 0
multiply both sides by 5 ---> t = 0
heck you work

1. -4k=12 ( add 2 to both sides)
k= 12/ -4
k= -3

2. if u mean (t/5)+3=3
then:
t/5=0 (take away 3 from both sides)
t=0

-4k - 2 = 10
-4k = 10 + 2
-4k = 12
k = 12/-4
k = -3
-----------------------
t/5 + 3 = 3
t/5 = 3 - 3
t/5 = 0
t = 5 * 0
t = 0

1. -4k = 10 +2 = 12
-4k=12
k=12/(-4)= -3
K= -3
2. t/5= 3-3 =0
t/5=0
t= 0

2)

t/5 = 3+3

t = 3-3 * (5)

t = 0

1)
-4k-2=10
-4k=12
k=-3

2)
t/5+3=3
t/5=0
t=0(5)
t=0

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