is this the correct answer and did i get the function notation correct?
13x-1 (0,infinity)u[13,0) or (neg. infinity,13]
13
-----
5
--- - 1
x
or h(x)=13 divided by 5/x-1
13x-1 (0,infinity)u[13,0) or (neg. infinity,13]
13
-----
5
--- - 1
x
or h(x)=13 divided by 5/x-1
-
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