I did the work but the answer is not logical. I'd like to double check.
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Area of a triangle = (base x height)/2
= 5*(5/8)/2
=(25/8)/2
=25/16 feet^2 which is about 1.6 feet^2
= 5*(5/8)/2
=(25/8)/2
=25/16 feet^2 which is about 1.6 feet^2
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b x h divided by 2.
To prove it, draw a perpendicular from the apex to the base, and you now have 2 right triangles, which as you know has an area of b x h divided by 2. Add the 2 areas together.
Here's one for you:
what is the area of a triangle with sides 3 ft, 2 ft and 5 ft?
To prove it, draw a perpendicular from the apex to the base, and you now have 2 right triangles, which as you know has an area of b x h divided by 2. Add the 2 areas together.
Here's one for you:
what is the area of a triangle with sides 3 ft, 2 ft and 5 ft?
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Area of a triangle = 1/2 (Base*Height)
= 1/2 ( 5*5/8)
= 25/16 or 1.5625 sq ft
= 1/2 ( 5*5/8)
= 25/16 or 1.5625 sq ft
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A = (1/2)bh
A = (1/2)(5)(5/8)
A = 1.5625ft^2
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A = (1/2)(5)(5/8)
A = 1.5625ft^2
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