there are four 2's, thirteen clubs, and one card in the intersection, thus the number of desirable cards is 4+13-1.
divide this by 52 for the answer.
divide this by 52 for the answer.
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52c2 = 1326 ways for any 2 cards
ways for (two) = 4
ways for (club) = 13
ways for (two of clubs) = 1
(4+13-1)/1326 = 0.012066365
ways for (two) = 4
ways for (club) = 13
ways for (two of clubs) = 1
(4+13-1)/1326 = 0.012066365
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Count the number of all of the twos/clubs in a deck of cards, and then divide by 52.