How would I compute the probability of randomly selecting an ace or heart from a deck of 52 cards

Probability = [number of ways of success] / [total number of possible ways]

How many aces ? How many hearts ? any overlap ?

P(ace or heart) = (4/52) + (13/52) - (1/52) = 16/52 = 4/13

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a deck of cards is fifty two their are four things (hearts, clubs, diamonds, and spades) each are 1/4 their are 13 cards in each thing (hearts, clubs, diamonds, and spades) each thing holds one of each

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace

so in total their is 4 of each in one deck

your questions was about aces right well if their are four aces in the deck of 52 so that is 4/52=1/13

now hearts that the probability of that is 13/52 because their is 13 cards in each thing(hearts, clubs, diamonds, and spades)

so that answers your question and this also applies with all other cards or things(hearts, clubs, diamonds, and spades) also

There are four aces in a deck of 52 so probability of selecting an ace is 4/52 or 1/13

There are 13 hearts in a deck of 52 so probability of selecting a heart is 13/52 or 1/4

If you want the probability of selecting an ace of hearts probability is 1/52

Pr = n(ace + heart - both) /52 = (4+13-1)/52 = 16/52 = 4/13 <--------