Two walkers left an intersection at the same time.One walked northward at an average speed of 3mph.The other walked westward at an average speed of 4mph.After how long will they be 1 mile apart?
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Imagine that you're looking at this from the sky. When they're one mile apart, the path they've taken and the distance apart will be a triangle.
One leg of the triangle will be (if time is x): 3x. The other will be 4x. Pythagoras gave us a^2 + b^2 = c^2 (for right triangles).
(3x)^2 + (4x)^2 = 1^2
9x^2 + 16x^2 = 1^2
25x^2 = 1
x = 1/5 (in hours)
So in minutes, that's 60 / 5 = 12 minutes
One leg of the triangle will be (if time is x): 3x. The other will be 4x. Pythagoras gave us a^2 + b^2 = c^2 (for right triangles).
(3x)^2 + (4x)^2 = 1^2
9x^2 + 16x^2 = 1^2
25x^2 = 1
x = 1/5 (in hours)
So in minutes, that's 60 / 5 = 12 minutes
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Let the time be x hours
( 3x)^2 + ( 4x)^2 = 1^2
25x^2 = 1
x^2 = 1/25
x = \/1/25 = 1/5 hours ANSWER = 12 minutes
( 3x)^2 + ( 4x)^2 = 1^2
25x^2 = 1
x^2 = 1/25
x = \/1/25 = 1/5 hours ANSWER = 12 minutes
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lmao ^