Together two pipes can fill a small reservoir in 2hours.Working alone Pipe1 can fill a reservoir in 1hour and 40minutes less time than Pipe2 can.How long would each pipe need to fill the reservoir by itself?
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So let x= pipe 1 and y= pipe 2
Then, x+y=120(minutes or 2 hrs)
But, we also have that x=y-100(minutes or 1hr 40 min)
Substitute y-100 in for x in the first equation to eliminate a variable.
So, y-100+y=120
then, y+y=220
So, 2y=220 and
y=110(minutes)
Plug in and solve for x
x+110=120
x=10
so Pipe one can fill in 10 minutes and pipe 2 in 110 minutes or 1 hr 50 minutes
You can confirm this by observing that together this would make 2 hours
Then, x+y=120(minutes or 2 hrs)
But, we also have that x=y-100(minutes or 1hr 40 min)
Substitute y-100 in for x in the first equation to eliminate a variable.
So, y-100+y=120
then, y+y=220
So, 2y=220 and
y=110(minutes)
Plug in and solve for x
x+110=120
x=10
so Pipe one can fill in 10 minutes and pipe 2 in 110 minutes or 1 hr 50 minutes
You can confirm this by observing that together this would make 2 hours
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If Pipe 1 working alone takes 1h and 40m, thent that would mean Pipe 2 takes 20 minutes.
Don't really see the Algreba involved...
Don't really see the Algreba involved...