f(x)=2x-x^2
textbook says x=0 and x=2...how?
textbook says x=0 and x=2...how?
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set the equation into this form first: f(x)=ax²+bx+c=0
which looks like this: f(x)=-x²+2x+0
x² is the first term (a) , 2x is the second (b) and 0 is the third (c)
then input the coefficients of these terms into the quadratic formula: x= (-b±√(b²-4ac)) / 2a
which looks like this:
x= (-2±√(2²-4(-1)(0))) / 2(-1)
x= (-2±√(2²)) /-2
x= (-2±√4) -2
x= (-2±2) /-2 *now both add and subtract 2 from -2 (at separate times), then divide by -2 to get the following answer:
x= (-2+2)/-2 = 0
x= (-2-2)/-2 = 2
I apologize if I used the wrong mathematical terminology, I'm still in high school lol.
which looks like this: f(x)=-x²+2x+0
x² is the first term (a) , 2x is the second (b) and 0 is the third (c)
then input the coefficients of these terms into the quadratic formula: x= (-b±√(b²-4ac)) / 2a
which looks like this:
x= (-2±√(2²-4(-1)(0))) / 2(-1)
x= (-2±√(2²)) /-2
x= (-2±√4) -2
x= (-2±2) /-2 *now both add and subtract 2 from -2 (at separate times), then divide by -2 to get the following answer:
x= (-2+2)/-2 = 0
x= (-2-2)/-2 = 2
I apologize if I used the wrong mathematical terminology, I'm still in high school lol.
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x(2 - x) = 0
x = 0 , 2
x = 0 , 2