A peculiar problem in geometrical drawing (engineering graphics)

I am giving a simplified version of the problem. Consider any straight, horizontal line ( actually, the hinge line between Vertical and Horizontal Plane in 1st angle orthographic projection ). A point A is located vertically 25 mm below any point on the line. A straight line AB which is 100 mm long is to be drawn such that the end B is 45 mm below that horizontal line (using standard tools). Calculation of angle between the horizontal line and AB OR computing the projection of AB on that horizontal line are not allowed. Is it all possible to get that unique straight line AB?

Using just drafting tools, first decide on any point A which is measured as 25 mm below the line. Draw a second line parallel to the first line but 45 mm below it. Set your compass at radius 100 mm. Using A as the center, draw arc through the second line. Where they intersect is point B. Yes, it is unique, except that, of course, such a circle will generally intersect that second line twice, giving points B and B'.

dy = 45 - 25

L = 100 = hypotenuse = sqrt (dx2 + dy2)

L2 = dx2 + dy2

dx = sqrt( L2 - dy2 )

(where L2 means L squared etc)

Yes