I have a question that says,
"find the value of each variable"
The problem looks like this:
m(the sign kinda looks like a less than except its more open kinda like an acute angle)BDJ= 7y +2, m(same sign again)JDR= 2y +7
So what I did was this:
7y+2= 2y + 7
5y= 5
y=1
Then I plugged it back into the y in the original problem and got 9 is this correct? If not can you show me the correct way to do it?
"find the value of each variable"
The problem looks like this:
m(the sign kinda looks like a less than except its more open kinda like an acute angle)BDJ= 7y +2, m(same sign again)JDR= 2y +7
So what I did was this:
7y+2= 2y + 7
5y= 5
y=1
Then I plugged it back into the y in the original problem and got 9 is this correct? If not can you show me the correct way to do it?
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I believe you are correct, because you would do:
7y+2=2y+7 (as you did)
7y-2y and 7 - 2
5y=5
And yeah y would equal 1.
And if you wanna check it you just plug it back in:
7(1)+2=2(1)+7
7+2=2+7
9=9
Good Job!
7y+2=2y+7 (as you did)
7y-2y and 7 - 2
5y=5
And yeah y would equal 1.
And if you wanna check it you just plug it back in:
7(1)+2=2(1)+7
7+2=2+7
9=9
Good Job!
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Read the sign you're referring to as "angle"
Angle BDJ = 7y+2
Angle JDR = 2y+7
If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.
Angle BDJ = 7y+2
Angle JDR = 2y+7
If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.
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Read the sign you're referring to as "angle"
Angle BDJ = 7y+2
Angle JDR = 2y+7
If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.
Angle BDJ = 7y+2
Angle JDR = 2y+7
If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.
-
you are correct