So I have 40 mA existing for .8min. How many coulomb's have passed through?
Initially .8min must be con. to seconds so:
48s.
and then Q= I(t) = (40x10^-3)(48)=1920x10^-3=1.2 C
My txtbook says 192 C but my calcuator says 1.92?
Thanks!
Initially .8min must be con. to seconds so:
48s.
and then Q= I(t) = (40x10^-3)(48)=1920x10^-3=1.2 C
My txtbook says 192 C but my calcuator says 1.92?
Thanks!
-
you have the right idea
but stick units in if you are unclear.
40 mA = 40 mC/s = 0.04 C/s
0.04 C/s x 48s = 1.92 C
but stick units in if you are unclear.
40 mA = 40 mC/s = 0.04 C/s
0.04 C/s x 48s = 1.92 C