Find the equation of the tangent line to the curve y=x*(sqrt (x) ) at the point (4,8)

Find the equation of the tangent line to the curve y=x*(sqrt (x) ) at the point (4,8)?

y=?

y = x*sqrt(x) = x*x^(1/2) = x^(3/2)
--> y' = (3/2)x^(1/2) = (3/2)sqrt(x)
At x = 4. y' = (3/2)sqrt(4) = (3/2)*2 = 3
So the tangent line to y at (4,8) is given by
(y-8) = 3(x-4)
--> y = 3x - 12 + 8
--> y = 3x - 4