What is the empirical formula
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What is the empirical formula

[From: ] [author: ] [Date: 11-09-28] [Hit: ]
so the molar mass of the oxide is 23*4.59/3.4=31.if you substract 23 from 31.05 , you find 8g .......
When 3.40 g Na burns in air, 4.59 g oxide is formed. What is the empirical formula of the oxide?

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Molar mass of Na is 23g

so the molar mass of the oxide is 23*4.59/3.4=31.05

if you substract 23 from 31.05 , you find 8g . this is the half of the weigth of 1 atom of oxygen. So, you have 2 atoms of Na for 1 atom oxygen and formula is Na2O
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