A sample of N2O5 was composed of 6.499 g of nitrogen and 18.55 g of oxygen. How many grams of oxygen would there in a sample of NO that contained 8.534 g of nitrogen?
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weight of N atom/weight of O atom = "Ratio" = (6.499/2)/18.55/5)
Since you have a 1:1 ratio in NO
then your answer is 8.535 /"Ratio"
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let's cheat.... ignore the first part as something is wrong.
just using periodic table.
8.534 * 16/14 = 9.753
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and what was wrong orignially is that I skipped a line and put in 8.5.. instead of 18.55 - sorry
retry ratio now
Since you have a 1:1 ratio in NO
then your answer is 8.535 /"Ratio"
-----------
let's cheat.... ignore the first part as something is wrong.
just using periodic table.
8.534 * 16/14 = 9.753
----
and what was wrong orignially is that I skipped a line and put in 8.5.. instead of 18.55 - sorry
retry ratio now
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Your question is ambiguous so I will just answer the second one.
Moles of nitrogen = 8.534 / 14 = 0.50
" " oxygen = 0.50 x 16 = 8.03g
Moles of nitrogen = 8.534 / 14 = 0.50
" " oxygen = 0.50 x 16 = 8.03g