A sample of N2O5 was composed of...
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A sample of N2O5 was composed of...

[From: ] [author: ] [Date: 11-09-30] [Hit: ]
-weight of N atom/weight of O atom = Ratio = (6.499/2)/18.then your answer is 8.lets cheat.........
A sample of N2O5 was composed of 6.499 g of nitrogen and 18.55 g of oxygen. How many grams of oxygen would there in a sample of NO that contained 8.534 g of nitrogen?

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weight of N atom/weight of O atom = "Ratio" = (6.499/2)/18.55/5)

Since you have a 1:1 ratio in NO

then your answer is 8.535 /"Ratio"

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let's cheat.... ignore the first part as something is wrong.

just using periodic table.

8.534 * 16/14 = 9.753

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and what was wrong orignially is that I skipped a line and put in 8.5.. instead of 18.55 - sorry

retry ratio now

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Your question is ambiguous so I will just answer the second one.
Moles of nitrogen = 8.534 / 14 = 0.50
" " oxygen = 0.50 x 16 = 8.03g
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