125x^3-64. i do not know how to factor this. and does anyone know how to simplify 32^(-2/5) in radical format?
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USE FORMULA a^3 - b^3 = ( a-b) ( a^2 + ab + b^2)
answer = ( 5x -4) ( 25x^2 +20x +16)
32 = 2^5
32^-2/5 = ( 2^5)^-2/5 = 2^-2 = 1/4 answer
answer = ( 5x -4) ( 25x^2 +20x +16)
32 = 2^5
32^-2/5 = ( 2^5)^-2/5 = 2^-2 = 1/4 answer
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Well the first one is the "sum or difference of two cubes". So (5x-4)(25x^2 + 20x + 16) You can look at my sources to see why.
Secondly 32^-2/5= 1/ 32^2/5 = 1 / root 5 (32^2). The important part is that any negative exponent means put it under one, and to the power of 1/2 is square root.
Secondly 32^-2/5= 1/ 32^2/5 = 1 / root 5 (32^2). The important part is that any negative exponent means put it under one, and to the power of 1/2 is square root.
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google it
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Sorry,. i can't help you