A pig rancher wants to enclose a rectangular area and then divide it into five pens with fencing parallel to o

I really need help with this question thank you so much

A pig rancher wants to enclose a rectangular area and then divide it into five pens with fencing parallel to one side of the rectangle (see the figure below). He has 570 feet of fencing available to complete the job. What is the largest possible total area of the five pens?

Do ur own homework

Seperating a rectangle into 5 pens requires 4 additional sides running through the middle. this gives you total fencing of 2L and 6S since 2L+2S = P, the perimeter around the outside. So

2L+6S = 570.
He wants to maximize area in the pens.
A = LW

Rearrange the first eqn to L=285-3S
A becomes

A = W(285-3W) = 285W-3W²

observe that this is a quadratic so it has a parabola shaped graph. Also notice that the squared term is negative indicating that this parabola opens downward. Then the vertex of this parabola must be the maximum value of the function f(x) = -3W² + 285W

Since given this problem I'm certain you are studying quadratics right now, and most likely studying methods for finding their vertex, I'll leave the rest to you.

Step 1: ask the pig farmer why he wants the pigs apart
Step 2: tell said farmer that segregation is against the law
Step 3: call PETA

It says "see figure below" but you forgot to include the figure.