Trig identities: Simplify

Could you simplify this trig ID

[(tan²x)(csc²x)-1]/[(cscx)(tan²x)(sinx…‡

THANKS. I forgot completely how to do this. Showing work would be appreciated!

Use tan²x = sin²x / cos²x and csc²x = 1/sin²x.

[(tan²x)(csc²x)-1]/[(cscx)(tan²x)(sinx)…‡
[sin²x/ (sin²xcos²x) - 1] / [(sin²xsinx)/(sinxcos²x)]
[1/cos²x - 1] / [sin²x/cos²x]
[(1 - cos²x) / cos²x) / [sin² x / cos²x]
[(1 - cos²x) / cos²x] * [cos²x / sin² x]
[1 - cos²x ] / sin²x
sin²x / sin²x
1

Edit: Yeah sorry I made a little mistake. The bigger problem is this symbol ‡, I do not know how or why it forms and I cannot get rid of it.

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[(tan²x)(csc²x)-1]/[(cscx)(tan²x)(sinx)

[(sin²x / cos²x)(1/sin²x)-1] / [(1/sinx)(sin²x / cos²x)(sinx)

[(1/cos²x)-1] / [(sin²x / cos²x)]

[(1/cos²x)-1] / [(sin²x / cos²x)]

[sec²x - 1] / tan²x

tan²x / tan²x = 1

one of the ways to solve trig identities is to change all terms into sin and cosine, and work from there.
google trig functions table, print one copy for your own need.