PPL GREAT AT MATH calculus!!! help!!
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PPL GREAT AT MATH calculus!!! help!!

[From: ] [author: ] [Date: 11-08-15] [Hit: ]
......
Please help me solve for the inverse of y=ln((cubed root of 5-x^3) +1)

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y=ln((cubed root of 5-x^3) +1)

e^y = (5-x^3)^(1/3) + 1
e^y - 1 = (5 - x^3)^(1/3)
(e^y - 1)^3 = 5 - x^3
x^3 = 5 - (e^y - 1)^3
x = (5 - (e^y - 1)^3)^(1/3)

Inverse:

y = (5 - (e^x - 1)^3)^(1/3)

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y = (5 - (e^x - 1)^3)^(1/3)
1
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