Perform the indicated operation and simplify: (10y²³- 3z²+ 4) - (3y²³+ 4z²- 2)

²³ means 5... I didn't find the 5... what's the name of this exercise? Polynomial? where can I find them to practice? Please solve the exercise ;)

Hello,

When you have powers higher than 3, use the following notation, that anybody understands in maths category : x^5

Then you have :

10y^5 - 3z^2 + 4 - 3y^5 - 4z^2 + 2 = 7y^5 - 7z^2 + 6

You can't go farther... I do not know how to name this exercise, sorry...

I hope i helped

Bye !

10^5 - 3z^2 + 4 - 3y^5 - 4z^2 + 2 <------ distribute the negative
7y^5 - 7z^2 + 6 <---------- add like terms
after this, i'm not sure what you want me to do, you didn't make it very clear in your question...

(10y^5 - 3z^2 + 4) - (3y^5 + 4z^2 - 2) =
10y^5 - 3z^2 + 4 - 3y^5 - 4z^2 + 2 =
7y^5 - 7z^2 + 6.

10y^5 - 3z^2 + 4 - 3y^5 + 4z^2 - 2 =
(10 - 3)y^5 + (4 - 3)z^2 + 4 - 2 =
7y^5 + z^2 + 2