2x + y = 8
x + y = 4
The lines intersect at
x + y = 4
The lines intersect at
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These are simultaneous equations, they can be solved by addition.
you need first to get rid of y or x to find the value of the other one:
I'll multiply the first equation by -1 to get red of y:
so, the two equations are
-2x-y = -8
x + y = 4
now, add the two equations you'll get
-x = -4 ---------> x = 4
now, substitute the value of x in any of the equations to get the value of y
4+y = 4 y =0
so, the lines intersect at (4,0)
you need first to get rid of y or x to find the value of the other one:
I'll multiply the first equation by -1 to get red of y:
so, the two equations are
-2x-y = -8
x + y = 4
now, add the two equations you'll get
-x = -4 ---------> x = 4
now, substitute the value of x in any of the equations to get the value of y
4+y = 4 y =0
so, the lines intersect at (4,0)
-
At the point they intersect, both are true for the same value of x and y , thus it is OK to combined the two equations.
2x + y = 8 .......i
x + y = 4..........ii
subtract ii from i
x + 0 = 4
x= 4
substitute in ii
4 + y = 4
y = 0
2x + y = 8 .......i
x + y = 4..........ii
subtract ii from i
x + 0 = 4
x= 4
substitute in ii
4 + y = 4
y = 0
-
(4,0)
mutiply the second equation by -1 u should get -x-y=-4 then add it to the 1st equation and u should get x=4 so u substitute it into any equation the second is easier so it would be 4+y=4 then subtract 4 from both sides so y=0
mutiply the second equation by -1 u should get -x-y=-4 then add it to the 1st equation and u should get x=4 so u substitute it into any equation the second is easier so it would be 4+y=4 then subtract 4 from both sides so y=0
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First put it in its original form:
y = -2x + 8 and
y = -x + 4
Then draw the line.
y = -2x + 8 and
y = -x + 4
Then draw the line.