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When I do the first row, I add 10 to 5 radical 2, so I get 15 radical 2 over 5, which simplifies to 3 radical 2. What am I doing wrong?
For the second row, I do 6 + 2 radical 6, which is 8 radical 6 over 6. I simplify this to 4 radical 6 over 3.
How does this simplification work?
When I do the first row, I add 10 to 5 radical 2, so I get 15 radical 2 over 5, which simplifies to 3 radical 2. What am I doing wrong?
For the second row, I do 6 + 2 radical 6, which is 8 radical 6 over 6. I simplify this to 4 radical 6 over 3.
How does this simplification work?
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First of all, 10+5 radical 2 is not 15 radical 2, because 15 radical 2 is equal to about 21, and 10+5 radical 2 is about 17. In fact, you cannot simplify 10+ 5 radical 2. (10+5 radical 2)/5= 10/5+5 radical 2/5=2+radical 2.
You've made the exact same problem for the second question, you can't add the radical term with the integer term.
You've made the exact same problem for the second question, you can't add the radical term with the integer term.
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Hi.. well seems you just got confused, but your answer checks...
In the first one (10+5(2)^.5)/5 its the same as writing (10/5)+ (5(x^.5)/5) here all fractions have exact results so you get 2+(x^.5) right?.. whats different on the second one?…
(6/6)+(2*(x^.5)/6)= 1+(x^.5)/3= (3+(x^.5))/3
Trust your knowledge, you had it right all along..
In the first one (10+5(2)^.5)/5 its the same as writing (10/5)+ (5(x^.5)/5) here all fractions have exact results so you get 2+(x^.5) right?.. whats different on the second one?…
(6/6)+(2*(x^.5)/6)= 1+(x^.5)/3= (3+(x^.5))/3
Trust your knowledge, you had it right all along..
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i think you are doing your addition wrong in the first row. you can't add 10+5 in this case since they aren't like terms. same thing with the second row.