Well first you have to find a factor of the equation (a value of x that will make h(x) = 0) which in this case would be 2, now u make whatever that value of x that made it equal zero into a negative and put an x in front of it so it would be (x-2). So basically lets replace x with a so if h(a) = 0 then a factor of the equation would be (x-a) then u use ling or synthetic division to end up with (x-2)(x^2-x-6) then factor further into (x-2)(x+2)(x-3).
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I believe it is already in intercept form (if you mean y-intercept).