How to write h(x)=x^3-3x^2-4x+12 in intercept form
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > How to write h(x)=x^3-3x^2-4x+12 in intercept form

How to write h(x)=x^3-3x^2-4x+12 in intercept form

[From: ] [author: ] [Date: 11-07-07] [Hit: ]
......
Well first you have to find a factor of the equation (a value of x that will make h(x) = 0) which in this case would be 2, now u make whatever that value of x that made it equal zero into a negative and put an x in front of it so it would be (x-2). So basically lets replace x with a so if h(a) = 0 then a factor of the equation would be (x-a) then u use ling or synthetic division to end up with (x-2)(x^2-x-6) then factor further into (x-2)(x+2)(x-3).

-
I believe it is already in intercept form (if you mean y-intercept).
1
keywords: form,to,How,12,intercept,write,in,How to write h(x)=x^3-3x^2-4x+12 in intercept form
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .