how do you do this???
A mixture containing 0.598 mol He(g). 0.293 mol Ne(g), and 0.294 mol Ar(g) is confined in a vessel of constant volume and temperature and a total pressure of 2.92 atm. calculate the partial pressure in atm of He gas.
answer is 1.47E0 atm
A mixture containing 0.598 mol He(g). 0.293 mol Ne(g), and 0.294 mol Ar(g) is confined in a vessel of constant volume and temperature and a total pressure of 2.92 atm. calculate the partial pressure in atm of He gas.
answer is 1.47E0 atm
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Partial Pressure = X * P(total)
Note: X = n1/ntotal
In this equation n1 = 0.598 mol He
So n total = 1.185 mol
P(total) = 2.92 atm
Partial Pressure = 0.598/1.185 x 2.92 atm = 1.47 atm
Note: X = n1/ntotal
In this equation n1 = 0.598 mol He
So n total = 1.185 mol
P(total) = 2.92 atm
Partial Pressure = 0.598/1.185 x 2.92 atm = 1.47 atm