Help me with this quadratic equation please, its easy!!!

Factor the following quadratic equation:

4x^2- 2x +1 =0

I know its simple... but I seriously can't remember how to do this ahha

You have to use the quadratic formula: x= [-b ± (square root of b^2 - 4ac)] / 2a

a = 4
b = -2
c = 1

"a" is equal to the coefficient of your "x^2" term. "b" is equal to the coefficient of your "x" term. and c is the constant in the equation.

Using the formula you should have:
x = [2 ± (square root of -2^2 - (4)(4)(1))] \ (2)(4)

or

x = [2 ± (square root of -12)] / 8

or

x = 2 ± (2i)(square root of 3) / 8

or

x = 1 ± i(square root of 3) / 4


^ ^ ^ ^ ^ that's your answer!

4(1²) – 2(1) + 1 = 3, so 1 is not a solution to f(x) = 0 (You have a polynomial, not an equation, so it does not have any solutions)

The expression 4x² – 2x + 1 had discriminant 4 – 16 < 0, so it has two complex conjugate roots and does not factor.

It does not factor. (B^2-4ac is negative)

4(1)^2-2(1)+1= 4-2+1=3

So no and no!

Good luck!

(2x-1)(2x-1)=0...
x=1/2

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wolframalpha,com