Finding surface area of solid generated about x-axis
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Finding surface area of solid generated about x-axis

Finding surface area of solid generated about x-axis

[From: ] [author: ] [Date: 11-07-05] [Hit: ]
find the surface area of the solid generated.-each cross section perpendicular to the axis of rotation will be a circle with a radius of the function defining its outmost limit, y=2x^(1/2). thus, each cross section, dV,......
the region bounded by the graphs of y=2sqrt(x), y=0, x=3, and x=8 is revolved about the x-axis. find the surface area of the solid generated.

-
each cross section perpendicular to the axis of rotation will be a circle with a radius of the function defining its outmost limit, y=2x^(1/2). thus, each cross section, dV, is equal to π(2x^(1/2))^2dx, or 4πxdx. Now you need to integrate between the limits, 3 and 8.

∫ from 3 to 8 of 4πxdx
2πx^2 from 3 to 8
2π(8)^2-2π(3)^2
2(64)π-2(9)π
128π-18π
110π

the answer is 110π cubic units
1
keywords: axis,of,area,surface,about,generated,solid,Finding,Finding surface area of solid generated about x-axis
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .