Solve the equation in the interval between 0 & 360 degrees. 2cot^2x - 7cotx + 3 = 0

2cot^2x - 7cotx + 3 This is a quadratic, think of cot^2 as x^2 (I will !!)

2x^2 - 7x + 3 = (2x - 1)(x - 3) = (2cotx - 1)(cotx - 3) = 0

So two solutions

2cotx = 1, cotx = 1/2 means tanx = 2

cotx = 3 means tanx = 1/3

Use the inverse tan function on your calculator (tan^-1)

x = tan^-1 (2) = 63.43 and 243.43 degrees

x = tan^-1 (1/3) = 18.43, 198.43 degrees Remember, tan is positive in Quads I & III

2cot²(x) - 7cot(x) + 3 =0

2cot²(x) - 6cot(x) - cot(x) + 3 = 0

(2cot(x) - 1)(cot(x) - 3) = 0

cot(x) = 1/2 --> tan(x) = 2

cot(x) = 3 --> tan(x) = 1/3

Solve for x.