The body in Fig. 10-37 is pivoted at O. Three forces act on it in the directions shown: FA = 8.8 N at point A, 9.8 m from O; FB = 15 N at point B, 2.4 m from O; and FC = 23 N at point C, 3.0 m from O. Taking the clockwise direction to be negative, what is the net torque about O?
Please combine the link for the image:
http://i175.
photobucket.com/
albums/w138/
kacortez/11_39
.gif
**My answer is 27.3408Nm
**And it's wrong.
**Why????
Please combine the link for the image:
http://i175.
photobucket.com/
albums/w138/
kacortez/11_39
.gif
**My answer is 27.3408Nm
**And it's wrong.
**Why????
-
Magnitude of Torque is defined : τ = r*F* sin α
--> τo = τA + τB + τC
= (9.8*8.8* sin 135) + (-2.4*15* sin 90) + (3*23* sin 150) = 59.48 Nm
--> τo = τA + τB + τC
= (9.8*8.8* sin 135) + (-2.4*15* sin 90) + (3*23* sin 150) = 59.48 Nm