Okay, here they are and this is all the given information. I don't get it!!! Please explain too.
GIVEN:
Part 1:
Volume of H2O: 200.0 mL H2O
Mass of NaOH: 2.535 g NaOH
Initial temperature in calorimeter: 24.2 °C
Final temperature in calorimeter: 27.8 °C
Part 2:
Volume of HCl solution: 100.5 mL HCl
Volume of NaOH solution: 100.0 mL NaOH
Initial temperature in calorimeter: 25.2 °C
Final temperature in calorimeter: 28.2 °C
QUESTIONS:
1. Write out a balanced “equation” for the process you investigated in Part I, including phase symbols.
2. Write out a balanced equation for the reaction you investigated in Part II, including phase symbols.
GIVEN:
Part 1:
Volume of H2O: 200.0 mL H2O
Mass of NaOH: 2.535 g NaOH
Initial temperature in calorimeter: 24.2 °C
Final temperature in calorimeter: 27.8 °C
Part 2:
Volume of HCl solution: 100.5 mL HCl
Volume of NaOH solution: 100.0 mL NaOH
Initial temperature in calorimeter: 25.2 °C
Final temperature in calorimeter: 28.2 °C
QUESTIONS:
1. Write out a balanced “equation” for the process you investigated in Part I, including phase symbols.
2. Write out a balanced equation for the reaction you investigated in Part II, including phase symbols.
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1. In part I the cations and anions are the same in both the chemicals so the solution will be a buffer solution and the balanced equation will be like this: H2O + NaOH -------> Buffersolution. 2. In part II the reaction will be a neutralization reaction that is: acid + base forming salt + water, so the balanced equation will be like this: HCl + NaOH --------> NaCl + H2O.