Rationalize The Numerator

[Sq(2+h)+Sq(2-h)]/(h)

Please help me rationalize the numerator of this! :)

[sqrt(2+h)+sqrt(2-h)]/(h) * [sqrt(2+h) - sqrt(2-h)]/[sqrt(2+h) - sqrt(2-h)]
= (2 + h - 2 + h) / {(h) * [sqrt(2+h) - sqrt(2-h)]}
= 2 / [sqrt(2+h) - sqrt(2-h)]

Not sure what you mean by "rationalize" the numerator. We rationalize to remove square roots from the denominator. However since the denominator has no square roots, then there is no need to rationalize. Or I guess you could multiply by (sqrt(2+h)-sqrt(2-h))/(sqrt(2+h)-sqrt(2-… This would give you (2+h-(2-h)/(h(sqrt(2+h)-sqrt(2-h))) = 2h/(h(sqrt(2+h)-sqrt(2-h))) = 2/(sqrt(2+h)-sqrt(2-h)).