Eliminate the parameter t to find a Cartesian equation for

x=T^2
Y=9+3T
X=AY^2+BY+C
I need
A=
B=
C=

X =T²
Y= 9 +3T
X= AY² +BY +C

Y = 9 +3√X
X = A(9 +3√X)² + B(9+3√X) +C
X = A(81 +9X +54√X)+ B(9 +3√X) + C
0= 81A +9B + C
X = 9AX
1 = 9A
A = 1/9
0= 54A√X +3B√X
3B = - 54A = -54(1/9) = -6
B = -2
from 0 =81(1/9) +9(-2) +C
C = 18 - 9 = 9
So A =1/9, B =-2, C =9