Are these calculations correct

Fe2O3 + 3CO --> Fe + 3CO2
A sample of the ore haematite contains 70% iron oxide.
Calculate the amount of iron oxide in 2000 tonnes of haematite.

I did : 2000 x 70/100 = 1400 tonnes

NEXT PART:
Calculate the amount of iron than can be extracted from 2000 tonnes of haematite.
(Relative Formula Mass: Fe= 56; O=16)

I did: Relative formula mass of Fe2O3 = 160

2000/160 = 12.5

12.5 x 56 = 700

So the answer is 700 tonnes.

First part is OK - You have 1400t of Fe2O3

How much iron is there in this mass of Fe2O3
From the equation:
1 mol Fe2O3 will produce 2 mol Fe
Molar mass Fe2O3 = 160g/mol as you calculated - so far so good
Molar mass Fe = 56g/mol 2mol = 112g

Mass Fe in 1400 tonnes Fe2O3 = 1400*112/160 = 980 tonnes of Fe will be produced.

You went wrong at the end - The amount of iron produced comes only from the 1400 tonnes of Fe2O3 - not from the 2000 tonnes of original ore.