Chem Question Please help, Will choose best answer

Reaction E? (volts)
Na+ + e- → Na -2.71
Cl2 + 2e- → 2Cl- 1.36
F2 + 2e- → 2F- 2.87
Which of the following is the best reducing agent?

A. F2

B. Na

C. F-

D. Cl2

sodium

its obviously not F2, or Cl2, as those are oxidizing agents
From the powerful strength of the F2 as an oxidizing agent (indicated by the voltage being 2.87), the F- product is not going to be a very strong reducing agent , and sodium (Na) is a POWERFUL reducing agent.
F- is weak as a reducing agent, because for it to reduce anything, the extremely strong oxidizing agent F2 is formed, and it would really want its extra electron back,
look what happens when sodium is placed in water : http://www.youtube.com/watch?v=fLJ4FH7q0EQ&feature=fvwrel

Sodium is the most negative value, so its the strongest reducing agent

If its positive, its a stronger oxidizing agent than hydrogen , if negative it will be a weaker oxidizing agent than hydrogen and a stronger reducing agent. The voltage indicated for lithium indicates that its a stronger reducing agent than sodium, but sodium is actually stronger, so there are a few exceptions to using the voltages to measure the strength of oxidizing/reducing potential, but in this case, sodium is definetely indicated as the strongest, and it correctly is

According to YOUR data, C. F-

Actual data has F2 +2e --> 2F- @ +2.87 making the answer B. Na


EDIT: Sorry I didn't realise the minus referred to the elemental charge, Answer B. Na.