Limit of Riemann sums help
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Limit of Riemann sums help

[From: ] [author: ] [Date: 12-04-30] [Hit: ]
Im new to this I cant grasp the steps of how to do these type of problems. Any help is appreciated!!!!=8/3+4=20/3.......
How do I express the definite integral from 0 to 2 of (5x-3x+x^2)dx as a limit of Riemann sums? Also how do I evaluate the limit? I'm new to this I can't grasp the steps of how to do these type of problems. Any help is appreciated!!!!

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THE GIVEN FUNCTION IS INTEGRAL 0 to 2 of x^2+5x-3x dx
=INTE 0 TO 2 OF x^2+2X dx
using property of integrals we have
int 0to2 x^2+2xdx =int0to2 x^2dx+int0to 202xdx
=8/3+4=20/3.
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