Calculus help, 10 pts best answer (absolute maximum and minimum problem)

I've tried twice but i keep getting it wrong. i must be messing up at the derivative.


Find the absolute maximum and absolute minimum of f on the indicated interval.

f(x) = (x-1)^2 times (x+1)^2/3 ; on [-4, 5]

what are the absolute maximum and minimum? thanks! please show work

round answers to two decimal places!

f'(x) = 2(x-1)*(x+1)^(2/3) + (x-1)^2*(2/3)(x+1)^-(1/3)

This equals 0 when x=1 and when x=-.5

These are your critical numbers.

Since you're looking for absolute maximum and absolute minimum, you also need to consider your endpoints, x=-4 and x=5

Plug your critical numbers and endpoints into f(x)

You'll find that the function has an absolute maximum of 52.831 at x=5
and has an absolute minimum of 0 when x=1

Is this correct?

http://www.wolframalpha.com/input/?i=the+derivative+of+%28x-1%29%5E2*%28x%2B1%29%5E%282%2F3%29


this always helped me :)) once you get the derivative solve for x and plug in the numbers int he original equation to mind the absolute min or max