Ho do you solve 3^(2x+2)=10

any help appreciated

(2x+2)log3 = log10
x = 0.047952

Natural log of both sides bring down 2x+2 divide by ln3 -2 divide by 2
Answer is x=(ln10/2ln3) -2

3^(2x + 2) = 10
log(3^(2x + 2)) = log10
(2x + 2)log3 = 1
2x + 2 = 1/log3
x = (1/log3 - 2)/2