hello
help me please!
help me please!
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To show that |x| - x >= 0, we just note that |x| >= x always.
To show that |x|-x <= 2|x|, we can break it into 2 cases:
Case 1: x >= 0. Then |x| = x, and so:
|x|-x = x - x = 0.
and clearly 0 <= 2|x|, so we are done.
Case 2: x < 0. Then |x| = -x, and so:
|x|-x = -x -x = 2x <= 2|x|
Done.
To show that |x|-x <= 2|x|, we can break it into 2 cases:
Case 1: x >= 0. Then |x| = x, and so:
|x|-x = x - x = 0.
and clearly 0 <= 2|x|, so we are done.
Case 2: x < 0. Then |x| = -x, and so:
|x|-x = -x -x = 2x <= 2|x|
Done.