I know 3 is one of them, but my teacher said there are 2 more...and then she said to put them in factored form. I know (x - 3) is part of the factored form, but I don't know the rest. :c
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Long division by (x-3) gives (x^2-2x-4)
(x-3)(x^2-2x-4)
x^2-2x = 4
x^2-2x+1 = 5
(x-1)^2 = 5
x-1 = +/-sqrt(5)
Zeros are 1+sqrt(5), 1-sqrt(5) and 3
(x-3)(x^2-2x-4)
x^2-2x = 4
x^2-2x+1 = 5
(x-1)^2 = 5
x-1 = +/-sqrt(5)
Zeros are 1+sqrt(5), 1-sqrt(5) and 3
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x^3 - 5x^2 +2x +12 = (x-3)(x -1 + √5)(x -1 -√5) =
= (x-3)(x + 1.24)(x - 3.24)
Hence, Zeros are :
3, 3.24, and -1.24 >==========================< ANSWER
= (x-3)(x + 1.24)(x - 3.24)
Hence, Zeros are :
3, 3.24, and -1.24 >==========================< ANSWER
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x^3 - 5x^2 +2x +12 =
(x-3)(x^2-2x-4)
x=3
x=1+sqrt5
x=1-sqrt5
(x-3)(x^2-2x-4)
x=3
x=1+sqrt5
x=1-sqrt5